Alkene Reactions: Hydroboration using BH3, H2O2, and NaOH
Anti-Markovnikov alcohols via hydroboration–oxidation (BH₃·THF; then H₂O₂, NaOH)
Borane–tetrahydrofuran (BH₃·THF) hydroborates an alkene syn, placing boron on the less substituted carbon. Basic hydrogen peroxide (H₂O₂/NaOH) then converts the C–B bond into a C–O bond with retention at the migrating carbon. The overall transformation is predictable and closed-shell—no carbocations, no rearrangements—and the syn relationship of the incoming H and OH is preserved in the alcohol product.
Quick Summary
- Reagents/conditions: Step 1 BH₃·THF (0–25 °C, anhydrous THF). Step 2 H₂O₂ + NaOH(aq) (0–25 °C).
- Outcome: Anti-Markovnikov hydration; H and OH add to the same face (overall syn addition).
- Regioselectivity: Boron targets the less substituted carbon; oxidation substitutes B with OH at that carbon.
- Stereochemistry: Syn hydroboration followed by retentive oxidation → syn H/OH in the product.
- No rearrangements: Entire pathway is closed-shell—no carbocations or radical “peroxide effect.”
Mechanism (6 Steps)
Class: Concerted hydroboration followed by peroxide oxidation and hydrolysis.
Hydroboration is stereospecific and repeats up to three times per BH₃ molecule, generating a trialkylborane.
NaOH activates H₂O₂ to deliver HOO⁻, which coordinates the electron-poor boron center.
The B→O migration keeps the migrating carbon’s stereochemistry, locking in the syn relationship.
Boron remains coordinated while the negatively charged oxygen readies for protonation.
Proton transfer neutralises the oxygen while boron prepares to exit as borate.
The former boron-bearing carbon now bears the OH group, and the hydrogen added in Step 1 remains syn.
Mechanistic Checklist
- Hydroboration is concerted and syn—do not draw carbocations or radicals.
- Boron binds the less substituted carbon; oxidation retains configuration at carbon.
- Each BH₃ can hydroborate three alkenes (trialkylborane stage).
- Bulky boranes (9-BBN, Sia₂BH) improve terminal selectivity but follow the same pathway.
- Hydrolysis removes boron completely; no rearrangements occur.
Worked Example
Multiple Alkenes & Selectivity
- Less hindered, electron-rich alkenes hydroborate fastest; BH₃ often adds to three double bonds before oxidation.
- Terminal selectivity improves with bulky boranes (9-BBN, Sia₂BH); directing effects (e.g., allylic OH) depend on the specific borane and conditions—no Zn chelation is involved in BH₃·THF hydroboration.
Practical Tips & Pitfalls
- Safety: BH₃·THF is reactive and fuming—handle cold, under inert atmosphere. H₂O₂ is an oxidizer; add slowly to control exotherms.
- Order of addition: Complete hydroboration before introducing NaOH/H₂O₂; peroxide without base is sluggish.
- Workup: Ensure full oxidation to remove boron; borates cling to glassware—rinse promptly.
- Avoid misconceptions: This is not the radical "peroxide effect" seen with HBr/ROOR; the entire sequence is polar and closed-shell.
Exam-Style Summary
- Reagents: BH₃·THF, then H₂O₂/NaOH.
- Mechanism: Syn hydroboration → peroxide attack on boron → retentive alkyl migration → base-assisted collapse → hydrolysis.
- Outcome: Anti-Markovnikov alcohol (syn H/OH), no rearrangements.
- Selectivity: B prefers the less substituted carbon; bulky boranes enhance terminal selectivity.
Interactive Toolbox
- Compare hydroboration–oxidation with acid-catalyzed hydration (Markovnikov, possible rearrangements) in the Reaction Solver.
- Export the six-step mechanism panels via the Mechanism Explorer.
FAQ / Exam Notes
Why is the addition anti-Markovnikov? The hydroboration transition state positions boron at the less hindered carbon; oxidation then maps B → OH at that carbon.
Is the addition syn or anti? Hydroboration is syn, and the oxidation step retains configuration—H and OH end up syn overall.
Can I use bulky boranes? Yes. 9-BBN or Sia₂BH improves terminal selectivity but proceeds through the same mechanism.
Do rearrangements occur? No. The pathway is closed-shell with no carbocations or radicals, so 1,2-shifts are absent.