Alcohol Reactions: Alcohol Halogenation Using PBr3

Alcohol → Alkyl Bromide with PBr₃ | OrgoSolver

Alcohol → Alkyl Bromide with PBr₃ (Primary/Secondary: SN2 Inversion; Tertiary: Not Suitable)

Phosphorus tribromide (PBr₃) swaps alcohol OH groups for bromine in a clean, closed-shell SN2 sequence. The oxygen first becomes a good leaving group (alkoxy-dibromophosphite), and bromide executes a backside attack that inverts configuration at the reacting carbon. Because no carbocation is involved, rearrangements are avoided — a major advantage over direct HX conditions. Primary and most secondary alcohols behave beautifully; tertiary and highly hindered substrates hardly move the needle.

Need to contrast options? Benchmark against the SOCl₂ playbook, the Appel reaction, or acid-driven HX substitutions when rearrangements or harsh acidity are in play.


Quick Summary


  • Reagents & conditions: PBr₃ (≈0.33 eq per OH) in dry ether or CH₂Cl₂, 0–25 °C; pyridine or another base often suppresses HBr buildup.
  • Scope: primary & secondary alcohols → alkyl bromides with inversion; tertiary substrates remain unchanged.
  • Mechanistic spine: alcohol oxygen attacks PBr₃ → alkoxy-dibromophosphite → bromide SN2 displacement → R–Br.
  • Selectivity: allylic systems may deliver SN2′ mixtures; benzylic substrates react rapidly but remain SN2.
  • Advantage: avoids carbocations/rearrangements that plague strong-acid HX routes.


Mechanism — PBr₃ (3 Frames)


Step 1 — Formation of the phosphorus ester (activation)

Alcohol oxygen attacks phosphorus of PBr₃; bromide leaves to form an alkoxy-dibromophosphite.
Alcohol oxygen attacks phosphorus, expelling Br⁻ and delivering an alkoxy-dibromophosphite. Br⁻ or added base removes the proton.

Step 2 — SN2 displacement by bromide (configuration inversion)

Bromide backside-attack displaces the O–PBr₂ leaving group in a concerted SN2 step.
Br⁻ attacks from the backside, ejecting the O–PBr₂ group and inverting the stereochemistry at carbon.

Step 3 — Workup / stoichiometry

Each PBr₃ converts three alcohols; aqueous workup furnishes phosphorous acid byproducts.
One PBr₃ activates up to three alcohols; aqueous quench yields H₃PO₃ plus the alkyl bromide.


Mechanistic Checklist


  • No carbocation: pathway stays closed-shell; hydride/methyl shifts and rearrangements are absent.
  • SN2 at carbon: a single backside attack gives Walden inversion at the reacting centre.
  • Substrate class: primary and most secondary alcohols excel; tertiary and neopentyl variants are effectively inert.
  • Allylic/benzylic: allylic substrates may deliver SN2′ mixtures; benzylic sites react quickly but remain SN2.
  • Acid management: HBr forms in situ; a base (pyridine, imidazole, Et₃N) prevents elimination or side reactions.


Edge Cases & Exam Traps


  • “Retention with PBr₃?” No — only one substitution at carbon occurs, so overall inversion is observed.
  • Allylic SN2′: expect mixtures if an allylic π-system is present; draw both primary SN2 and SN2′ products.
  • Competing E2: minimal under cold, neutralized conditions; rises with hindered secondary substrates or excess HBr.
  • Tertiary alcohols: essentially no reaction — acid-promoted HX routes or other halogenating agents are required.
  • Neighboring heteroatoms: sulfur/phosphorus handles can chelate PBr₃; keep glassware dry and add base judiciously.


Worked Examples


Secondary, chiral centre (inversion)

(S)-2-butanol under PBr₃
(S)-2-butanol substrate PBr3 reagent card (R)-2-bromobutane product

(S)-2-butanol undergoes backside attack to give (R)-2-bromobutane — a single Walden inversion with no rearrangement.

Primary (clean displacement)

1-hexanol under PBr₃
1-hexanol substrate PBr3 reagent card 1-bromohexane product

Primary alcohols substitute cleanly: 1-hexanol delivers 1-bromohexane in high yield with negligible side reactions.

Allylic (SN2 vs SN2′ mixture)

3-buten-2-ol (allylic) under PBr₃
Allylic alcohol substrate PBr3 reagent card SN2 bromide product SN2′ bromide product

Allylic systems deliver mixtures: direct SN2 gives 2-bromobut-3-ene, while SN2′ attack shifts bromide to the terminal carbon (3-bromobut-1-ene).

Tertiary (not suitable)

tert-Butanol with PBr₃
tert-Butanol substrate PBr3 reagent card No substitution outcome

Tertiary centres are too hindered for concerted backside attack, so PBr₃ offers no useful substitution — use HX or another halogenating strategy instead.


Practical Tips


  • Keep it dry: PBr₃ is moisture-sensitive; dry glassware/solvent and add alcohol to reagent (never the reverse).
  • Use a base: pyridine, imidazole, or Hunig’s base mops up HBr and suppresses elimination.
  • Temperature control: 0 °C → rt covers most cases; colder runs help rein in SN2′ for allylic systems.
  • Stoichiometry: ≈0.33 eq PBr₃ per OH (or slight excess) ensures full conversion for sluggish substrates.
  • Workup: quench with cold aqueous NaHCO₃/Na₂CO₃, vent carefully, and segregate phosphorus-containing waste.


Exam-Style Summary


PBr₃ converts primary/secondary alcohols to alkyl bromides by first forming an alkoxy-dibromophosphite and then promoting an SN2 displacement that inverts configuration. Rearrangements are off the table, allylic substrates can show SN2′ mixtures, and tertiary centres are a non-starter — reach for HX or other halogenating tactics instead.


Interactive Toolbox


  • Mechanism Solver — render the three PBr₃ frames with electron pushing and toggle SN2′ arrows for allylic inputs.
  • Reaction Solver — compare PBr₃ versus HX outcomes (rearrangement risk, stereochemical control, product identity).
  • IUPAC Namer — confirm R–Br product names from your drawn substrates without exposing structural encodings.