Aldol Reactions: Addition vs. Condensation (Base-Catalyzed)

Aldol reactions are base-catalyzed carbonyl reactions that form a new C–C bond via an enolate. For most college organic chemistry problems, the key is conditions: cold/dilute base stops at the β-hydroxy carbonyl (aldol addition), while heat (Δ) drives dehydration to the α,β-unsaturated carbonyl (aldol condensation, E1cb).



Quick Summary

  • NaOH, cold/dilutealdol additionβ-hydroxy carbonyl
  • NaOH, heat (Δ)aldol condensationα,β-unsaturated carbonyl (dehydration via E1cb)


Conditions at a Glance

ConditionsProduct
NaOH (dilute), coldβ-Hydroxy carbonyl (aldol addition)
NaOH, Δ (heat)α,β-Unsaturated carbonyl (aldol condensation)


Mechanism

Mechanism overview

Aldol reaction mechanism overview

Aldol Addition (Steps 1–3)

Step 1: Form the enolate

Base removes an α‑H to give an enolate (the nucleophile).

Aldol reaction step 1: enolate formation

Step 2: Make the C–C bond

The enolate attacks a carbonyl to give an alkoxide (new C–C bond).

Aldol reaction step 2: carbon-carbon bond formation

Step 3: Protonate

Protonation gives the β-hydroxy carbonyl (aldol addition product).

Aldol reaction step 3: protonation to form the beta-hydroxy carbonyl

If the problem says cold/dilute base, stop after Step 3 (aldol addition).


Aldol Condensation (Steps 4–5)

If the problem shows heat (Δ), dehydration continues to the condensation product:

Step 4: Deprotonate (E1cb)

Base removes an α‑H again to set up elimination.

Aldol condensation step 4: deprotonation (E1cb)

Step 5: Eliminate (dehydration)

Elimination gives the α,β-unsaturated carbonyl (conjugated product).

Aldol condensation step 5: E1cb dehydration to alpha,beta-unsaturated carbonyl


Worked Examples

Example A: Self-Aldol Condensation

2 eq

Acetaldehyde (reactant)
NaOH, heat conditions
Crotonaldehyde (product)

Acetaldehyde self-condensation → crotonaldehyde


Example B: Crossed Aldol (Claisen–Schmidt)

  • Benzaldehyde has no α‑hydrogens, so it can’t form an enolate (electrophile only).

Enolate

Acetaldehyde (enolate source)
+

Electrophile

Benzaldehyde (electrophile)
NaOH, heat conditions
Cinnamaldehyde (product)

Acetaldehyde + Benzaldehyde → cinnamaldehyde


Example C: Intramolecular Aldol (Ring Formation)

  • Intramolecular aldol cyclizations usually favor 5‑ and 6‑membered rings.
2,5-hexanedione (reactant)
NaOH, heat conditions
3-methylcyclopent-2-enone (product)

2,5-hexanedione → 3-methylcyclopent-2-enone (5-membered ring)



Exam Quick Reference

Clue in ProblemProduct
"NaOH, cold" or "dilute"β-Hydroxy carbonyl (addition)
"NaOH, Δ" or "heat"α,β-Unsaturated carbonyl (condensation)
Benzaldehyde + ketoneCrossed aldol (benzaldehyde = electrophile only)
Dicarbonyl + baseIntramolecular → ring

Key points:

  • Heat drives dehydration (E1cb elimination)
  • Conjugated product is usually (E) (trans)
  • Self-condensation doubles carbons minus H₂O


Interactive Toolbox

NaOH, cold: aldol addition conditions

Use NaOH (cold/dilute) to stop at the β-hydroxy carbonyl (aldol addition).

NaOH, heat: aldol condensation conditions

Add heat (Δ) to drive dehydration to the α,β-unsaturated carbonyl (aldol condensation).

  • Mechanism Solver — step through aldol addition/condensation with electron-pushing arrows.
  • Reaction Solver — draw a carbonyl and predict the aldol product under cold vs heat conditions.
  • IUPAC Namer — name the β-hydroxy carbonyl or α,β-unsaturated carbonyl product.


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