Ketone α-Halogenation under Base (NaOH → X₂)

Ketone α‑Halogenation under Basic Conditions (NaOH → X₂)

Hydroxide removes an α-proton to generate the enolate, which then attacks molecular halogen (X₂ = Cl₂ or Br₂) to form the α‑halo ketone. Each substitution increases the acidity of the remaining α‑hydrogens, so base-promoted halogenation readily repeats (polyhalogenation). When a methyl ketone is driven with excess base/halogen, the cycle continues to the haloform reaction, fragmenting to a carboxylate plus CHX₃. Use this guide alongside the acid-catalyzed companion (mono-halogenation via enols) to highlight the contrasting behavior.


Quick Summary

  • Reagents/conditions: NaOH(aq) to generate the enolate, followed by X₂ (Cl₂ or Br₂) at 0–25 °C in water or aqueous alcohol.
  • Outcome: Mono α‑halogenation with limited reagents; di-/tri‑halogenation under excess X₂/base.
  • Trends: Br₂ ≈ Cl₂ for rate; excess halogen/base pushes successive substitutions and haloform for methyl ketones.
  • Regioselectivity: Kinetic α-site (less hindered) dominates with NaOH; stronger, non-equilibrating bases exaggerate this bias.
  • Stereochemistry: α‑Centers racemize via the planar enolate; newly formed stereocenters are racemic.

Mechanism — Base Path via Enolate (Steps A–J)


Step 1: hydroxide removes the alpha proton to give the enolate.
**Step 1 – Deprotonation (A–C):** OH⁻ abstracts the α‑H, pushing C–H electrons into C=C (enolate π) and shifting the C=O π pair onto oxygen (O⁻ resonance form).
Step 2: enolate carbon attacks X₂ while X⁻ departs and the carbonyl reforms.
**Step 2 – Electrophilic halogenation (D–F):** The enolate carbon donates into X₂ (D); X–X cleaves to X⁻ (E); the oxygen lone pair collapses to C=O as C–X forms (F).
Step 3: water protonates the alkoxide, regenerating hydroxide.
**Step 3 – Protonation (G):** Solvent (H₂O) protonates the alkoxide, returning the neutral α‑halo ketone and regenerating OH⁻.
Optional Step 4: repeated deprotonation and halogenation under excess reagents.
**Step 4 – Polyhalogenation (J):** Excess halogen/base re-enolizes the same α-carbon, driving di-/tri-halogenation (autocatalysis) and priming the haloform loop for methyl ketones.

Haloform Branch (Methyl Ketones; Steps K–N)

  • After three successive halogenations at a methyl ketone, OH⁻ adds to the carbonyl (Step K) to give a tetrahedral intermediate.
  • Collapse of that intermediate expels CX₃⁻ (Step L), leaving a carboxylate (base form of the acid).
  • CX₃⁻ deprotonates solvent water (Step M/N), generating haloform (CHX₃) and regenerating hydroxide. Acidic workup converts the carboxylate to the free acid.

Mechanistic Checklist (Exam Focus)

  • Base pathway = enolate chemistry (contrast with the acid enol route).
  • Polyhalogenation is expected if reagents are not limited.
  • Methyl ketones proceed to haloform (CHX₃) when excess base/halogen is present.
  • α‑Racemization is unavoidable; do not promise retention/inversion.
  • Enolate formation sets the regiochemistry; subsequent halogenations stay on the same α-carbon.
  • Strong base/heat can trigger E2 of α‑halo ketones to give enones (flag as a side reaction).

Worked Examples


2-Butanone → 3-Bromo-2-butanone

2-butanone reactant + NaOH reagent icon 2-butanone enolate intermediate + Br₂ addition icon 3-bromo-2-butanone product

Limiting Br₂ (≈1 equiv) at low temperature delivers mostly the mono-brominated product, showcasing the kinetic preference for the less hindered α-site of 2-butanone.

2-Pentanone → Poly-α-chloro Products

2-pentanone reactant + NaOH reagent icon 2-pentanone enolate intermediate + Cl₂ addition icon poly-chlorinated 2-pentanone products

Supplying 2–3 equivalents of Cl₂ under basic conditions autocatalyzes further α-chlorination, yielding α,α-dichloro and α,α,α-trichloro products unless the reaction is quenched early.

Acetone → Haloform (CHX₃) + Acetate

Acetone reactant + NaOH reagent icon Acetone enolate intermediate + Br₂ addition icon Haloform (CHI₃) and acetate products

Excess Br₂ with NaOH drives exhaustive α-halogenation of acetone; hydroxide then cleaves the C–C bond to give bromoform (CHBr₃) and acetate (haloform reaction).


Scope & Limitations

  • Good: Ketones with α‑hydrogens, especially benzylic or allylic sites.
  • Poly-prone: Methyl ketones or substrates with a single α-site accumulate CX₃ rapidly.
  • Sluggish: Heavily hindered α-sites; insufficient base or halogen slows successive substitutions.
  • No reaction: α‑Free ketones (e.g., benzophenone) cannot form the enolate.
  • Compare: Acid pathway delivers mono-halogenation at the thermodynamic enol site.

Practical Tips

  • Limit mono: Meter X₂ (≤1 equiv), keep the mixture cool, and quench promptly.
  • Drive poly: Provide excess X₂/OH⁻ and allow time; monitor for haloform when methyl ketones are present.
  • Workup: Quench residual halogen with Na₂S₂O₃, then acidify if a neutral α‑halo ketone or carboxylic acid is desired.
  • Safety: Handle halogens and CHX₃ cautiously; provide ventilation and appropriate waste disposal.

Exam-Style Summary

NaOH forms the enolate (arrows A–C); X₂ traps it (D–F); water reprotonates (G). Excess halogen/base repeats the loop on the same α-carbon, and methyl ketones advance to the haloform branch (K–N) to give carboxylate + CHX₃. Contrast with the acid route, which mono-halogenates via the thermodynamic enol.


Related Reading


Interactive Toolbox

  • Mechanism Solver — animate enolate formation, X₂ capture, the polyhalogenation loop, and haloform toggle (Cl₂/Br₂, equivalents, methyl-ketone flag).
  • Reaction Solver — predict mono vs. poly outcomes, flag haloform conditions automatically, and surface competing E2 warnings for α‑halo ketones.
  • IUPAC Namer — confirm α‑halo ketone names and haloform/carboxylate outputs without exposing SMILES strings.